Water Damage Restoration Technician (WRT) Certification Practice Test

In a Class 2 water loss containing 15,000 cubic feet, what is the initial required capacity in pints per day using conventional refrigerant dehumidifiers?

1. 100 PPD

2. 250 PPD

3. 375 PPD

4. 500 PPD

The correct answer is: 375 PPD

For a Class 2 water loss, which typically involves a significant amount of moisture in materials such as wall cavities, insulation, and furnishings, the calculation for initial dehumidifier capacity is crucial. Class 2 water losses are characterized by a relative humidity over 50% and can affect up to two feet above the floor. To determine the required dehumidification capacity, a general guideline is that for every 1,000 cubic feet of space, 20 pints per day (PPD) of dehumidification capacity is needed. In this case, with a volume of 15,000 cubic feet, the calculation would follow this guideline: 15,000 cubic feet / 1,000 cubic feet = 15 15 * 20 PPD = 300 PPD However, because the situation is classified as Class 2, moisture conditions can require additional capacity to effectively manage humidity levels and promote rapid drying. This is particularly important to prevent further damage and promote efficient drying. In practical applications, restoration professionals often round up the requirements or consider safety margins in their calculations. Therefore, while the calculated requirement is 300 PPD, restoration practices often lead to the recommendation of selecting a dehumidifier system with a slightly higher